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fix(curriculum): improve description and hint for clarity in Step 31 (#53233)

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Dominic Lim
2024-01-18 01:13:52 +08:00
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parent 8b66218146
commit fb308e5508
1 changed files with 2 additions and 2 deletions
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curriculum/challenges/english/15-javascript-algorithms-and-data-structures-22/learn-functional-programming-by-building-a-spreadsheet/64497e0e5e5a2c2329785af4.md
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@@ -9,11 +9,11 @@ dashedName: step-31
Spreadsheet software typically uses `=` at the beginning of a cell to indicate a calculation should be used, and spreadsheet functions should be evaluated.
Update your `if` condition to also check if the first character of `value` is `=`.
Use the `&&` operator to add a second condition to your `if` statement that also checks if the first character of `value` is `=`.
# --hints--
Your `if` condition should also check if the first character of `value` is `=`. You may use `[0]`, `.startsWith()`, or `.charAt(0)`.
You should use the `&&` operator to add a second condition to your `if` statement that also checks if the first character of `value` is `=`. You may use `[0]`, `.startsWith()`, or `.charAt(0)`.
```js
assert.match(code, /const\s+update\s*=\s*\(?\s*event\s*\)?\s*=>\s*\{\s*const\s+element\s*=\s*event\.target;?\s*const\s+value\s*=\s*element\.value\.replace\(\s*\/\\s\/g\s*,\s*('|"|`)\1\s*\);?\s*if\s*\(\s*(!value\.includes\(\s*element\.id\s*\)\s*&&\s*(?:value\[0\]\s*===\s*('|"|`)=\3|value\.charAt\(0\)\s*===\s*('|"|`)=\4|value\.startsWith\(('|"|`)=\5\))|(?:value\[0\]\s*===\s*('|"|`)=\6|value\.charAt\(0\)\s*===\s*('|"|`)=\7|value\.startsWith\(('|"|`)=\8\))\s*\|\|\s*!value\.includes\(\s*element\.id\s*\))\s*\)\s*\{\s*\}/);